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If (n) is the smallest positive integer for which the decimal expansion of (\frac{n}{2^3\cdot 3^2\cdot 5\cdot 7}) becomes terminating, what is the value of (n)?

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Answer and explanation

Correct answer: (63)

Step 1: For a terminating decimal, the reduced denominator must contain only (2) and (5). Step 2: The denominator has extra prime factors (3^2) and (7), so (n) must contain (3^2\cdot 7=63). Step 3: When the smallest value is asked, cancel only the unwanted prime factors.

Related tags

Minimum-FactorTerminating-DecimalPrime-FactorisationReal-Numbers

Frequently asked questions

What is the correct answer to this question?

(63)

Why is this the correct answer?

Step 1: For a terminating decimal, the reduced denominator must contain only (2) and (5). Step 2: The denominator has extra prime factors (3^2) and (7), so (n) must contain (3^2\cdot 7=63). Step 3: When the smallest value is asked, cancel only the unwanted prime factors.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Decimal expansion of rational numbers.

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