0 reads0 ratings0 helpful
If (n=2^8\times3^5\times5^6), by which smallest number should (n) be divided to make it a perfect cube?
Advertisement
Answer and explanation
Correct answer: (2^2\times3^2)
Step 1: In a perfect cube, every exponent must be a multiple of 3. Step 2: Reduce (2^8) to (2^6) by dividing by (2^2), and reduce (3^5) to (3^3) by dividing by (3^2). Step 3: So the smallest divisor is (2^2\times3^2).
Frequently asked questions
What is the correct answer to this question?
(2^2\times3^2)
Why is this the correct answer?
Step 1: In a perfect cube, every exponent must be a multiple of 3. Step 2: Reduce (2^8) to (2^6) by dividing by (2^2), and reduce (3^5) to (3^3) by dividing by (3^2). Step 3: So the smallest divisor is (2^2\times3^2).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement