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Class 10MathematicsReal NumbersFundamental Theorem of ArithmeticExpertLevel 5
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If (n=2^7\times3^6\times5^3\times19), by which number must (n) be divisible?

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Answer and explanation

Correct answer: 69255

Step 1: (69255=3^6\times5\times19). Step 2: All these prime factors are present in (n) with sufficient powers. Step 3: Therefore, (n) must be divisible by 69255.

Related tags

DivisibilityPrime-FactorisationExpert

Frequently asked questions

What is the correct answer to this question?

69255

Why is this the correct answer?

Step 1: (69255=3^6\times5\times19). Step 2: All these prime factors are present in (n) with sufficient powers. Step 3: Therefore, (n) must be divisible by 69255.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.

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