If (m=2^3\times3\times5) and (n=2^2\times3^2), what is the HCF of (m) and (n)?

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Answer and explanation

Correct answer: (12)

Step 1: The common prime factors are (2) and (3). Step 2: The smaller powers are (2^2) and (3). Step 3: (2^2\times3=12), so the HCF is (12).

What is the correct answer to this question?

(12)

Why is this the correct answer?

Step 1: The common prime factors are (2) and (3). Step 2: The smaller powers are (2^2) and (3). Step 3: (2^2\times3=12), so the HCF is (12).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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