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If \(x\) and \(y\) are non-zero real numbers and \(\left(x^{-3}y^{2}\right)^k=x^{-12}y^{8}\), what is the value of \(k\)?

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Answer and explanation

Correct answer: 4

Using the exponent rule \((ab)^k=a^k b^k\), the left-hand side becomes \(x^{-3k}y^{2k}\). Comparing the exponents of the same bases gives \(-3k=-12\) and \(2k=8\), and both equations yield \(k=4\). Exam tip: When monomials with the same bases are equal, compare the corresponding exponents.

Related tags

Laws Of ExponentsExponent ComparisonMonomialsReal NumbersPolynomials

Frequently asked questions

What is the correct answer to this question?

4

Why is this the correct answer?

Using the exponent rule \((ab)^k=a^k b^k\), the left-hand side becomes \(x^{-3k}y^{2k}\). Comparing the exponents of the same bases gives \(-3k=-12\) and \(2k=8\), and both equations yield \(k=4\). Exam tip: When monomials with the same bases are equal, compare the corresponding exponents.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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