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If (L) is the LCM of (98), (147), and (245), what is the value of (L)?

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Answer and explanation

Correct answer: (1470)

Step 1: (98=2\times7^2), (147=3\times7^2), and (245=5\times7^2). Step 2: The highest powers are (2), (3), (5), and (7^2), so LCM (=2\times3\times5\times49=1470). Step 3: Take the common highest power (7^2) only once.

Related tags

Real-NumbersLcmPrime-Factorisation

Frequently asked questions

What is the correct answer to this question?

(1470)

Why is this the correct answer?

Step 1: (98=2\times7^2), (147=3\times7^2), and (245=5\times7^2). Step 2: The highest powers are (2), (3), (5), and (7^2), so LCM (=2\times3\times5\times49=1470). Step 3: Take the common highest power (7^2) only once.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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