If in an AP (a_7=31) and (a_{19}=103), what is the value of (a_{34})?
Answer and explanation
Correct answer: (193)
(d=\frac{103-31}{19-7}=6), so (a_{34}=103+15\times6=193). First find (d), then move forward from the nearer term.
Frequently asked questions
What is the correct answer to this question?
(193)
Why is this the correct answer?
(d=\frac{103-31}{19-7}=6), so (a_{34}=103+15\times6=193). First find (d), then move forward from the nearer term.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Finding the $n$th term of an AP.