यदि किसी समान्तर श्रेणी में \(a_7=31\) और \(a_{19}=103\) है तो \(a_{34}\) का मान क्या होगा?

If in an AP \(a_7=31\) and \(a_{19}=103\), what is the value of \(a_{34}\)?

Explanation opens after your attempt
Correct Answer

B. (193)

Step 1

Concept

\(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

Step 2

Why this answer is correct

The correct answer is B. (193). \(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

Step 3

Exam Tip

\(d=\frac{103-31}{19-7}=6\) इसलिए \(a_{34}=103+15\times6=193\)। पहले (d) निकालकर निकट पद से आगे बढ़ें।

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यदि किसी समान्तर श्रेणी में \(a_7=31\) और \(a_{19}=103\) है तो \(a_{34}\) का मान क्या होगा? / If in an AP \(a_7=31\) and \(a_{19}=103\), what is the value of \(a_{34}\)?

Correct Answer: B. (193). Explanation: \(d=\frac{103-31}{19-7}=6\) इसलिए \(a_{34}=103+15\times6=193\)। पहले (d) निकालकर निकट पद से आगे बढ़ें। / \(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

Which concept should I revise for this Mathematics MCQ?

\(d=\frac{103-31}{19-7}=6\), so \(a_{34}=103+15\times6=193\). First find (d), then move forward from the nearer term.

What exam hint can help solve this Mathematics question?

\(d=\frac{103-31}{19-7}=6\) इसलिए \(a_{34}=103+15\times6=193\)। पहले (d) निकालकर निकट पद से आगे बढ़ें।