If (H) is the HCF of (99), (165), and (231), what is the value of (H)?
Answer and explanation
Correct answer: (33)
Step 1: (99=3^2\times11), (165=3\times5\times11), and (231=3\times7\times11). Step 2: The common smaller powers are (3) and (11), so HCF (=33). Step 3: Choose only primes present in all three numbers.
Frequently asked questions
What is the correct answer to this question?
(33)
Why is this the correct answer?
Step 1: (99=3^2\times11), (165=3\times5\times11), and (231=3\times7\times11). Step 2: The common smaller powers are (3) and (11), so HCF (=33). Step 3: Choose only primes present in all three numbers.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.