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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 12
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If (H) is the HCF of (221), (323), and (391), what is the value of (H)?

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Answer and explanation

Correct answer: (17)

Step 1: (221=13\times17), (323=17\times19), and (391=17\times23). Step 2: The common prime in all three is (17), so the HCF is (17). Step 3: Identify the prime common to all three numbers.

Related tags

Real-NumbersHcfThree-Numbers

Frequently asked questions

What is the correct answer to this question?

(17)

Why is this the correct answer?

Step 1: (221=13\times17), (323=17\times19), and (391=17\times23). Step 2: The common prime in all three is (17), so the HCF is (17). Step 3: Identify the prime common to all three numbers.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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