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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 10
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If (H) is the HCF of (121), (143), and (169), what is the value of (H)?

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Answer and explanation

Correct answer: (1)

Step 1: (121=11^2), (143=11\times13), and (169=13^2). Step 2: No prime factor is common to all three numbers, so the HCF is (1). Step 3: For three numbers, a common factor must appear in all of them.

Related tags

Real-NumbersHcfThree-Numbers

Frequently asked questions

What is the correct answer to this question?

(1)

Why is this the correct answer?

Step 1: (121=11^2), (143=11\times13), and (169=13^2). Step 2: No prime factor is common to all three numbers, so the HCF is (1). Step 3: For three numbers, a common factor must appear in all of them.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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  1. 1If the product of two numbers is 3780 and their LCM is 315, what is their HCF?
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  5. 5What is the LCM of (40) and (60)?
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