If (H) and (L) are respectively the HCF and LCM of (420), (660), and (924), what is (L\div H)?
Answer and explanation
Correct answer: (385)
Step 1: (420=2^2\times3\times5\times7), (660=2^2\times3\times5\times11), and (924=2^2\times3\times7\times11). Step 2: (H=2^2\times3=12) and (L=2^2\times3\times5\times7\times11=4620), so (L\div H=385). Step 3: For three numbers, check common primes first and then all distinct primes.
Frequently asked questions
What is the correct answer to this question?
(385)
Why is this the correct answer?
Step 1: (420=2^2\times3\times5\times7), (660=2^2\times3\times5\times11), and (924=2^2\times3\times7\times11). Step 2: (H=2^2\times3=12) and (L=2^2\times3\times5\times7\times11=4620), so (L\div H=385). Step 3: For three numbers, check common primes first and then all distinct primes.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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