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If (H) and (L) are respectively the HCF and LCM of (252), (315), and (420), what is (L\div H)?
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Answer and explanation
Correct answer: (60)
Step 1: (252=2^2\times3^2\times7), (315=3^2\times5\times7), and (420=2^2\times3\times5\times7). Step 2: (H=3\times7=21) and (L=2^2\times3^2\times5\times7=1260), so (L\div H=60). Step 3: For three numbers, find HCF and LCM by their separate rules.
Frequently asked questions
What is the correct answer to this question?
(60)
Why is this the correct answer?
Step 1: (252=2^2\times3^2\times7), (315=3^2\times5\times7), and (420=2^2\times3\times5\times7). Step 2: (H=3\times7=21) and (L=2^2\times3^2\times5\times7=1260), so (L\div H=60). Step 3: For three numbers, find HCF and LCM by their separate rules.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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