यदि \(x^2-11x+30=0\) की जड़ें \(\alpha,\beta\) हैं, तो \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\) का मान क्या है?
If \(\alpha,\beta\) are roots of \(x^2-11x+30=0\), what is \(\frac{\alpha+1}{\alpha-1}+\frac{\beta+1}{\beta-1}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{29}{10}\)
Concept
The roots are (5) and (6). Hence \(\frac{6}{4}+\frac{7}{5}=\frac{15}{10}+\frac{14}{10}=\frac{29}{10}\).
Why this answer is correct
The correct answer is A. \(\frac{29}{10}\). The roots are (5) and (6). Hence \(\frac{6}{4}+\frac{7}{5}=\frac{15}{10}+\frac{14}{10}=\frac{29}{10}\).
Exam Tip
जड़ें (5) और (6) हैं। इसलिए \(\frac{6}{4}+\frac{7}{5}=\frac{15}{10}+\frac{14}{10}=\frac{29}{10}\)।
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