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If \(\alpha,\beta\) are roots of \(8x^2-31x+15=0\), what is \((\alpha-\beta)^2\)?यदि \(8x^2-31x+15=0\) के मूल \(\alpha,\beta\) हैं, तो \((\alpha-\beta)^2\) क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: \( \frac{481}{64}\) / \(\frac{481}{64}\)\( \frac{481}{64}\) / \(\frac{481}{64}\)
\((\alpha-\beta)^2=(\alpha+\beta)^2-4\alpha\beta=\left(\frac{31}{8}\right)^2-\frac{15}{2}=\frac{481}{64}\). In exams, convert fractions to a common denominator.\((\alpha-\beta)^2=(\alpha+\beta)^2-4\alpha\beta=\left(\frac{31}{8}\right)^2-\frac{15}{2}=\frac{481}{64}\) है। परीक्षा में भिन्नों को समान हर में बदलें।
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