If (\alpha) and (\beta) are zeroes of (x^2-3x-10), what is (\alpha^2\beta+\alpha\beta^2)?यदि (x^2-3x-10) के शून्यक (\alpha) और (\beta) हैं, तो (\alpha^2\beta+\alpha\beta^2) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (-30)(-30)
(\alpha^2\beta+\alpha\beta^2=\alpha\beta(\alpha+\beta)). Here (\alpha\beta=-10) and (\alpha+\beta=3), so the value is (-30).(\alpha^2\beta+\alpha\beta^2=\alpha\beta(\alpha+\beta)) होता है। यहां (\alpha\beta=-10) और (\alpha+\beta=3), इसलिए मान (-30) है।
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.