यदि द्विघात बहुपद \(x^2-6x+k\) के शून्यक \(\alpha\) और \(\beta\) हैं तथा \(\alpha^2+\beta^2=20\) है, तो (k) का मान क्या होगा?
If \(\alpha\) and \(\beta\) are zeroes of the quadratic polynomial \(x^2-6x+k\) and \(\alpha^2+\beta^2=20\), what is the value of (k)?
Explanation opens after your attempt
A. (8)
Concept
Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).
Why this answer is correct
The correct answer is A. (8). Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).
Exam Tip
\(\alpha+\beta=6\) और (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। इसलिए (20=36-2k) से (k=8) मिलता है।
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