यदि द्विघात बहुपद \(x^2-6x+k\) के शून्यक \(\alpha\) और \(\beta\) हैं तथा \(\alpha^2+\beta^2=20\) है, तो (k) का मान क्या होगा?

If \(\alpha\) and \(\beta\) are zeroes of the quadratic polynomial \(x^2-6x+k\) and \(\alpha^2+\beta^2=20\), what is the value of (k)?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).

Step 2

Why this answer is correct

The correct answer is A. (8). Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).

Step 3

Exam Tip

\(\alpha+\beta=6\) और (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। इसलिए (20=36-2k) से (k=8) मिलता है।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि द्विघात बहुपद \(x^2-6x+k\) के शून्यक \(\alpha\) और \(\beta\) हैं तथा \(\alpha^2+\beta^2=20\) है, तो (k) का मान क्या होगा? / If \(\alpha\) and \(\beta\) are zeroes of the quadratic polynomial \(x^2-6x+k\) and \(\alpha^2+\beta^2=20\), what is the value of (k)?

Correct Answer: A. (8). Explanation: \(\alpha+\beta=6\) और (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। इसलिए (20=36-2k) से (k=8) मिलता है। / Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).

Which concept should I revise for this Mathematics MCQ?

Here \(\alpha+\beta=6\) and (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta). So (20=36-2k), giving (k=8).

What exam hint can help solve this Mathematics question?

\(\alpha+\beta=6\) और (\alpha-2+\beta-2=\(\alpha+\beta\)2-2\alpha\beta) होता है। इसलिए (20=36-2k) से (k=8) मिलता है।