यदि \(x^2-12x+32=0\) के मूल \(\alpha\) और \(\beta\) हैं तो \(\frac{\alpha^2+\beta^2}{\alpha\beta}\) का मान क्या है?
If \(\alpha\) and \(\beta\) are roots of \(x^2-12x+32=0\), what is the value of \(\frac{\alpha^2+\beta^2}{\alpha\beta}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{5}{2}\)
Concept
Here \(\alpha+\beta=12\) and \(\alpha\beta=32\). \(\alpha^2+\beta^2=144-64=80\), and \(\frac{80}{32}=\frac{5}{2}\).
Why this answer is correct
The correct answer is A. \(\frac{5}{2}\). Here \(\alpha+\beta=12\) and \(\alpha\beta=32\). \(\alpha^2+\beta^2=144-64=80\), and \(\frac{80}{32}=\frac{5}{2}\).
Exam Tip
यहां \(\alpha+\beta=12\) और \(\alpha\beta=32\) है। \(\alpha^2+\beta^2=144-64=80\) और \(\frac{80}{32}=\frac{5}{2}\) है।
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