यदि \(\alpha\) और \(\beta\) समीकरण \(2x^2-7x+3=0\) के मूल हैं तो \(\alpha+\beta-\alpha\beta\) का मान क्या है?

If \(\alpha\) and \(\beta\) are roots of \(2x^2-7x+3=0\), what is the value of \(\alpha+\beta-\alpha\beta\)?

Explanation opens after your attempt
Correct Answer

A. (2)

Step 1

Concept

Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\). Therefore \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\).

Step 2

Why this answer is correct

The correct answer is A. (2). Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\). Therefore \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\).

Step 3

Exam Tip

यहां \(\alpha+\beta=\frac{7}{2}\) और \(\alpha\beta=\frac{3}{2}\) है। इसलिए \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\) होगा।

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Mathematics Answer, Explanation and Revision Hints

यदि \(\alpha\) और \(\beta\) समीकरण \(2x^2-7x+3=0\) के मूल हैं तो \(\alpha+\beta-\alpha\beta\) का मान क्या है? / If \(\alpha\) and \(\beta\) are roots of \(2x^2-7x+3=0\), what is the value of \(\alpha+\beta-\alpha\beta\)?

Correct Answer: A. (2). Explanation: यहां \(\alpha+\beta=\frac{7}{2}\) और \(\alpha\beta=\frac{3}{2}\) है। इसलिए \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\) होगा। / Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\). Therefore \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\).

Which concept should I revise for this Mathematics MCQ?

Here \(\alpha+\beta=\frac{7}{2}\) and \(\alpha\beta=\frac{3}{2}\). Therefore \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\).

What exam hint can help solve this Mathematics question?

यहां \(\alpha+\beta=\frac{7}{2}\) और \(\alpha\beta=\frac{3}{2}\) है। इसलिए \(\alpha+\beta-\alpha\beta=\frac{7}{2}-\frac{3}{2}=2\) होगा।