यदि \(\alpha=5+\sqrt{6}\) और \(\beta=5-\sqrt{6}\), तो \(\frac{1}{\alpha}+\frac{1}{\beta}\) क्या है?
If \(\alpha=5+\sqrt{6}\) and \(\beta=5-\sqrt{6}\), what is \(\frac{1}{\alpha}+\frac{1}{\beta}\)?
Explanation opens after your attempt
Correct Answer
A. \(\frac{10}{19}\)
Concept
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\). Here the sum is (10) and product is (25-6=19), so the answer is \(\frac{10}{19}\).
Why this answer is correct
The correct answer is A. \(\frac{10}{19}\). \(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\). Here the sum is (10) and product is (25-6=19), so the answer is \(\frac{10}{19}\).
Exam Tip
\(\frac{1}{\alpha}+\frac{1}{\beta}=\frac{\alpha+\beta}{\alpha\beta}\) होता है। यहाँ योग (10) और गुणनफल (25-6=19), इसलिए उत्तर \(\frac{10}{19}\) है।
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