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If a number has prime factorisation (2^7\times3^5\times5^4\times11), how many prime factors are there if repetition is counted?
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Answer and explanation
Correct answer: 17
Step 1: To count with repetition, add the exponents. Step 2: (2^7) gives 7, (3^5) gives 5, (5^4) gives 4, and 11 gives 1 factor. Step 3: Total (7+5+4+1=17), so the answer is 17.
Frequently asked questions
What is the correct answer to this question?
17
Why is this the correct answer?
Step 1: To count with repetition, add the exponents. Step 2: (2^7) gives 7, (3^5) gives 5, (5^4) gives 4, and 11 gives 1 factor. Step 3: Total (7+5+4+1=17), so the answer is 17.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
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