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If a number has prime factorisation (2^3\times3^2\times7^2), how many prime factors does it have including repetition?
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Answer and explanation
Correct answer: 7
Step 1: To count with repetition, add the exponents. Step 2: (2^3) gives 3, (3^2) gives 2, and (7^2) gives 2 factors. Step 3: Total (3+2+2=7), so the answer is 7.
Frequently asked questions
What is the correct answer to this question?
7
Why is this the correct answer?
Step 1: To count with repetition, add the exponents. Step 2: (2^3) gives 3, (3^2) gives 2, and (7^2) gives 2 factors. Step 3: Total (3+2+2=7), so the answer is 7.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
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