0 reads0 ratings0 helpful
If a number has prime factorisation (2^{10}\times3^8\times5^7\times19^2), how many prime factors are there if repetition is counted?
Advertisement
Answer and explanation
Correct answer: 27
Step 1: To count with repetition, add the exponents. Step 2: (2^{10}) gives 10, (3^8) gives 8, (5^7) gives 7, and (19^2) gives 2 factors. Step 3: Total (10+8+7+2=27), so the answer is 27.
Frequently asked questions
What is the correct answer to this question?
27
Why is this the correct answer?
Step 1: To count with repetition, add the exponents. Step 2: (2^{10}) gives 10, (3^8) gives 8, (5^7) gives 7, and (19^2) gives 2 factors. Step 3: Total (10+8+7+2=27), so the answer is 27.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement