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If a number has only (2^3) and (5^2) in its prime factorisation, by which number must it be divisible?

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Answer and explanation

Correct answer: 10

Step 1: (2^3) and (5^2) contain both factors 2 and 5. Step 2: The product of 2 and 5 is 10, so the number must be divisible by 10. Step 3: Divisibility can be quickly identified from prime factors.

Related tags

DivisibilityPrime-FactorisationMedium

Frequently asked questions

What is the correct answer to this question?

10

Why is this the correct answer?

Step 1: (2^3) and (5^2) contain both factors 2 and 5. Step 2: The product of 2 and 5 is 10, so the number must be divisible by 10. Step 3: Divisibility can be quickly identified from prime factors.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.

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