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If (a \neq 0) and (b \neq 0), what is the simplified form of (\dfrac{(a^{-2}b^3)^2}{(ab^{-1})^{-1}})?

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Answer and explanation

Correct answer: (,\dfrac{b^5}{a^3},)

The numerator is ((a^{-2}b^3)^2=a^{-4}b^6) and the denominator is ((ab^{-1})^{-1}=a^{-1}b), so the answer is (\dfrac{b^5}{a^3}). In exams, apply the outside power first.

Related tags

PolynomialsNegative-ExponentsAlgebraic-SimplificationDivision

Frequently asked questions

What is the correct answer to this question?

(,\dfrac{b^5}{a^3},)

Why is this the correct answer?

The numerator is ((a^{-2}b^3)^2=a^{-4}b^6) and the denominator is ((ab^{-1})^{-1}=a^{-1}b), so the answer is (\dfrac{b^5}{a^3}). In exams, apply the outside power first.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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