If (a=2^6\times3^2\times5\times13) and (b=2^3\times3^5\times5^2), what is (\frac{\text{LCM}}{\text{HCF}})?
Answer and explanation
Correct answer: (2^3\times3^3\times5\times13)
Step 1: HCF is (2^3\times3^2\times5), and LCM is (2^6\times3^5\times5^2\times13). Step 2: On division, subtract powers to get (2^3\times3^3\times5\times13). Step 3: In ratios, subtract exponents of the same base.
Frequently asked questions
What is the correct answer to this question?
(2^3\times3^3\times5\times13)
Why is this the correct answer?
Step 1: HCF is (2^3\times3^2\times5), and LCM is (2^6\times3^5\times5^2\times13). Step 2: On division, subtract powers to get (2^3\times3^3\times5\times13). Step 3: In ratios, subtract exponents of the same base.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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