If (96), (160), and (224) are to be divided into the maximum number of equal parts, what will be the number of parts?
Answer and explanation
Correct answer: (32)
Step 1: The maximum number of equal parts is found by HCF. Step 2: (96=2^5\times3), (160=2^5\times5), and (224=2^5\times7), so HCF (=2^5=32). Step 3: In maximum equal division questions, identify HCF.
Frequently asked questions
What is the correct answer to this question?
(32)
Why is this the correct answer?
Step 1: The maximum number of equal parts is found by HCF. Step 2: (96=2^5\times3), (160=2^5\times5), and (224=2^5\times7), so HCF (=2^5=32). Step 3: In maximum equal division questions, identify HCF.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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