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Subjects
Class 10MathematicsPolynomialsOperations on real numbers and the laws of exponentsExpertLevel 43
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If (6^{x}=216) and (36^{y}=216), what is the value of (x+y)?

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Answer and explanation

Correct answer: (\frac{9}{2})

Since (216=6^{3}), (x=3). Also (36^{y}=(6^{2})^{y}=6^{2y}=6^{3}), so (y=\frac{3}{2}) and the sum is (\frac{9}{2}).

Related tags

Exponent EquationCommon BaseReal Numbers

Frequently asked questions

What is the correct answer to this question?

(\frac{9}{2})

Why is this the correct answer?

Since (216=6^{3}), (x=3). Also (36^{y}=(6^{2})^{y}=6^{2y}=6^{3}), so (y=\frac{3}{2}) and the sum is (\frac{9}{2}).

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Polynomials. Topic: Operations on real numbers and the laws of exponents.

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