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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 12
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If (192), (288), and (480) are to be divided into the maximum number of equal parts, what will be the number of parts?

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Answer and explanation

Correct answer: (96)

Step 1: The maximum number of equal parts is found by HCF. Step 2: (192=2^6\times3), (288=2^5\times3^2), and (480=2^5\times3\times5), so HCF (=2^5\times3=96). Step 3: In maximum equal division, take the smallest common powers.

Related tags

Real-NumbersHcfEqual-Parts

Frequently asked questions

What is the correct answer to this question?

(96)

Why is this the correct answer?

Step 1: The maximum number of equal parts is found by HCF. Step 2: (192=2^6\times3), (288=2^5\times3^2), and (480=2^5\times3\times5), so HCF (=2^5\times3=96). Step 3: In maximum equal division, take the smallest common powers.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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