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If (180=2^2\times3^2\times5), how many distinct prime factors does 180 have?
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Answer and explanation
Correct answer: 3
Step 1: Look at distinct prime factors, not their powers. Step 2: In (180=2^2\times3^2\times5), the distinct primes are 2, 3, and 5. Step 3: Even with a higher power, count the same prime once.
Frequently asked questions
What is the correct answer to this question?
3
Why is this the correct answer?
Step 1: Look at distinct prime factors, not their powers. Step 2: In (180=2^2\times3^2\times5), the distinct primes are 2, 3, and 5. Step 3: Even with a higher power, count the same prime once.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: Fundamental Theorem of Arithmetic.
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