0 reads0 ratings0 helpful
If (128), (192), and (320) are to be divided into the maximum number of equal parts, what will be the number of parts?
Advertisement
Answer and explanation
Correct answer: (64)
Step 1: The maximum number of equal parts is found by HCF. Step 2: (128=2^7), (192=2^6\times3), and (320=2^6\times5), so HCF (=2^6=64). Step 3: For maximum equal division, take the smallest common power.
Frequently asked questions
What is the correct answer to this question?
(64)
Why is this the correct answer?
Step 1: The maximum number of equal parts is found by HCF. Step 2: (128=2^7), (192=2^6\times3), and (320=2^6\times5), so HCF (=2^6=64). Step 3: For maximum equal division, take the smallest common power.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
Advertisement