समीकरण \(x^2-2\sqrt{7}x+3=0\) के मूल कैसे होंगे?
How will the roots of \(x^2-2\sqrt{7}x+3=0\) be?
Explanation opens after your attempt
Correct Answer
A. वास्तविक, अपरिमेय और भिन्नReal, irrational and distinct
Concept
Here (D=\(2\sqrt{7}\)2-4(1)(3)=16). The roots are \(\sqrt{7}\pm2\), so they are irrational and distinct.
Why this answer is correct
The correct answer is A. वास्तविक, अपरिमेय और भिन्न / Real, irrational and distinct. Here (D=\(2\sqrt{7}\)2-4(1)(3)=16). The roots are \(\sqrt{7}\pm2\), so they are irrational and distinct.
Exam Tip
यहाँ (D=\(2\sqrt{7}\)2-4(1)(3)=16) है। मूल \(\sqrt{7}\pm2\) होंगे, इसलिए वे अपरिमेय और भिन्न हैं।
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