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Which point on the line \(2x-7y=14\) is obtained by putting \(x=0\)?समीकरण \(2x-7y=14\) वाली रेखा पर \(x=0\) रखने पर कौन-सा बिंदु प्राप्त होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Point \((0,-2)\)बिंदु \((0,-2)\)
Substituting \(x=0\) gives \(2(0)-7y=14\), so \(-7y=14\) and \(y=-2\). Therefore, the point is \((0,-2)\). Option C results from setting \(y=0\), which gives the x-intercept rather than the required point. Exam tip: Set \(x=0\) to find the y-intercept.\(x=0\) रखने पर \(2(0)-7y=14\), अर्थात् \(-7y=14\), इसलिए \(y=-2\) मिलता है। अतः बिंदु \((0,-2)\) है। विकल्प C में \(y=0\) रखकर \(x=7\) मिलता है, इसलिए वह x-अवरोध है, माँगा गया बिंदु नहीं। परीक्षा टिप: y-अवरोध ज्ञात करने के लिए हमेशा \(x=0\) रखें।
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