A worker lays (50) bricks on the first day and (10) more bricks each next day. How many bricks will he lay on the (6)th day?
Answer and explanation
Correct answer: 100
The number of bricks laid each day forms an arithmetic progression with first term \(a=50\) and common difference \(d=10\). The sixth term is \(a_6=a+(6-1)d=50+5\times10=100\). Therefore, the correct answer is 100. Note that 90 is the number of bricks laid on the fifth day. Exam tip: Use \(a_n=a+(n-1)d\) for the nth term of an AP.
Frequently asked questions
What is the correct answer to this question?
100
Why is this the correct answer?
The number of bricks laid each day forms an arithmetic progression with first term \(a=50\) and common difference \(d=10\). The sixth term is \(a_6=a+(6-1)d=50+5\times10=100\). Therefore, the correct answer is 100. Note that 90 is the number of bricks laid on the fifth day. Exam tip: Use \(a_n=a+(n-1)d\) for the nth term of an AP.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
Student feedback
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
