A worker lays (40) bricks on the first day and (8) more bricks each next day. How many bricks will he lay on the (6)th day?
Answer and explanation
Correct answer: 80
The number of bricks laid each day forms an AP with first term 40 and common difference 8. The sixth term is \(a_6=a+(6-1)d=40+5\times8=80\). Therefore, the worker will lay 80 bricks on the sixth day. Note that 72 is the number of bricks on the fifth day. Exam tip: Use \(a_n=a+(n-1)d\) to avoid counting the first day incorrectly.
Frequently asked questions
What is the correct answer to this question?
80
Why is this the correct answer?
The number of bricks laid each day forms an AP with first term 40 and common difference 8. The sixth term is \(a_6=a+(6-1)d=40+5\times8=80\). Therefore, the worker will lay 80 bricks on the sixth day. Note that 72 is the number of bricks on the fifth day. Exam tip: Use \(a_n=a+(n-1)d\) to avoid counting the first day incorrectly.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
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