A sweet shop sells (28) boxes on the first day and (4) more boxes each next day. How many boxes are sold on the (10)th day?
Answer and explanation
Correct answer: \(64\)
The sales increase by 4 boxes each day, so they form an arithmetic progression. Here, \(a=28\), \(d=4\), and \(n=10\). Thus, \(a_{10}=a+(n-1)d=28+(10-1)\times4=64\). Therefore, 64 boxes are sold on the 10th day. The option \(68\) results from incorrectly adding 10 increases; there are only 9 increases from the first day to the 10th day. Exam tip: use \(n-1\) in the formula for the \(n\)th term of an AP.
Frequently asked questions
What is the correct answer to this question?
\(64\)
Why is this the correct answer?
The sales increase by 4 boxes each day, so they form an arithmetic progression. Here, \(a=28\), \(d=4\), and \(n=10\). Thus, \(a_{10}=a+(n-1)d=28+(10-1)\times4=64\). Therefore, 64 boxes are sold on the 10th day. The option \(68\) results from incorrectly adding 10 increases; there are only 9 increases from the first day to the 10th day. Exam tip: use \(n-1\) in the formula for the \(n\)th term of an AP.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
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