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A shopkeeper wants to pack (96), (144), and (240) sweets equally into boxes. What is the greatest number of sweets that can be put in each box?

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Answer and explanation

Correct answer: (48)

Step 1: Since all sweets must be divided equally, find the HCF. Step 2: (96=2^5\times 3), (144=2^4\times 3^2), and (240=2^4\times 3\times 5). The common smallest part is (2^4\times 3=48). Step 3: For greatest equal grouping, use HCF.

Related tags

Hcf Word ProblemGroupingPrime Factorisation

Frequently asked questions

What is the correct answer to this question?

(48)

Why is this the correct answer?

Step 1: Since all sweets must be divided equally, find the HCF. Step 2: (96=2^5\times 3), (144=2^4\times 3^2), and (240=2^4\times 3\times 5). The common smallest part is (2^4\times 3=48). Step 3: For greatest equal grouping, use HCF.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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