A number leaves remainder (0) when divided by (168), (210), and (280). What is the smallest such number?
Answer and explanation
Correct answer: (840)
Step 1: Remainder (0) means the number is exactly divisible by all three numbers. Step 2: (168=2^3\times3\times7), (210=2\times3\times5\times7), and (280=2^3\times5\times7), so LCM (=2^3\times3\times5\times7=840). Step 3: For the smallest divisible number, find the LCM.
Frequently asked questions
What is the correct answer to this question?
(840)
Why is this the correct answer?
Step 1: Remainder (0) means the number is exactly divisible by all three numbers. Step 2: (168=2^3\times3\times7), (210=2\times3\times5\times7), and (280=2^3\times5\times7), so LCM (=2^3\times3\times5\times7=840). Step 3: For the smallest divisible number, find the LCM.
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.
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