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Class 10MathematicsReal NumbersHCF and LCM using prime factorisationExpertLevel 12
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A number is divisible by both (2^4\times3^2\times5) and (2^6\times3\times7). What will be the value of the smallest such number?

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Answer and explanation

Correct answer: (20160)

Step 1: The smallest number divisible by both is their LCM. Step 2: The highest powers are (2^6), (3^2), (5), and (7), so the value is (64\times9\times5\times7=20160). Step 3: Include all required prime powers together.

Related tags

Real-NumbersLcmMultiple

Frequently asked questions

What is the correct answer to this question?

(20160)

Why is this the correct answer?

Step 1: The smallest number divisible by both is their LCM. Step 2: The highest powers are (2^6), (3^2), (5), and (7), so the value is (64\times9\times5\times7=20160). Step 3: Include all required prime powers together.

Which subject and chapter does this question cover?

This is a Class 10 Mathematics question. Chapter: Real Numbers. Topic: HCF and LCM using prime factorisation.

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