A medicine dose is (10) mg on the first day and increases by (5) mg each next day. What is the dose on the (6)th day?
Answer and explanation
Correct answer: 35 mg
The doses form an arithmetic progression with first term \(a=10\) mg and common difference \(d=5\) mg. The dose on day \(n\) is \(a_n=a+(n-1)d\). Thus, \(a_6=10+(6-1)\times5=35\) mg. Option A results from counting too few increases. Exam tip: In the \(n\)th-term formula of an AP, the number of increases is always \(n-1\).
Frequently asked questions
What is the correct answer to this question?
35 mg
Why is this the correct answer?
The doses form an arithmetic progression with first term \(a=10\) mg and common difference \(d=5\) mg. The dose on day \(n\) is \(a_n=a+(n-1)d\). Thus, \(a_6=10+(6-1)\times5=35\) mg. Option A results from counting too few increases. Exam tip: In the \(n\)th-term formula of an AP, the number of increases is always \(n-1\).
Which subject and chapter does this question cover?
This is a Class 10 Mathematics question. Chapter: Arithmetic Progressions (AP). Topic: Word problems based on APs.
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