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For which value will the lines (3x+ay=15) and (9x+12y=47) be distinct and parallel?किस मान पर (3x+ay=15) और (9x+12y=47) की रेखाएं समांतर अलग-अलग होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (a=4)(a=4)
For parallel lines, (\frac{3}{9}=\frac{a}{12}), so (a=4). Since (\frac{15}{47}\neq\frac{1}{3}), they will not be coincident.समांतर के लिए (\frac{3}{9}=\frac{a}{12}), इसलिए (a=4)। चूंकि (\frac{15}{47}\neq\frac{1}{3}), वे संपाती नहीं होंगी।
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