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If the only intersection of two lines is ((r,s)) and (2r+s=10), (r-2s=-3), what is (r+s)?यदि दो रेखाओं का एकमात्र प्रतिच्छेद ((r,s)) है और (2r+s=10), (r-2s=-3), तो (r+s) क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (7)(7)
From the first equation, (s=10-2r). Substitution gives (r=\frac{17}{5}) and (s=\frac{16}{5}), so (r+s=\frac{33}{5}); none of the options match, so option verification is essential.पहले से (s=10-2r), रखने पर (r-2(10-2r)=-3), इसलिए (r=\frac{17}{5}) और (s=\frac{16}{5})। अतः (r+s=\frac{33}{5}), इसलिए दिए विकल्पों में कोई सही नहीं; ऐसे प्रश्न में विकल्प-सत्यापन जरूरी है।
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