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For which value will (2x+ay=10) and (6x+9y=31) be distinct parallel lines?किस मान पर (2x+ay=10) और (6x+9y=31) की रेखाएं समांतर अलग-अलग होंगी?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (a=3)(a=3)
For parallel lines, (\frac{2}{6}=\frac{a}{9}), so (a=3). Since (\frac{10}{31}\neq\frac{1}{3}), the lines are not coincident.समांतर के लिए (\frac{2}{6}=\frac{a}{9}), इसलिए (a=3)। चूंकि (\frac{10}{31}\neq\frac{1}{3}), रेखाएं संपाती नहीं होंगी।
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