0 reads0 ratings0 helpful
If the lines (2x+ky=8) and (4x+6y=12) are parallel but not coincident, what is the value of (k)?यदि (2x+ky=8) और (4x+6y=12) की रेखाएं समांतर हों और संपाती न हों, तो (k) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (3)(3)
For parallel lines, (\frac{2}{4}=\frac{k}{6}), so (k=3). Also (\frac{8}{12}\neq\frac{1}{2}), so they are not coincident.समांतर के लिए (\frac{2}{4}=\frac{k}{6}), इसलिए (k=3)। साथ ही (\frac{8}{12}\neq\frac{1}{2}), इसलिए वे संपाती नहीं हैं।
Student feedback
Was this question useful?
Was this question useful?
👍 0 Helpful 👎 0 Not helpful
Difficulty
Easy0%
Medium0%
Hard0%
Was the explanation clear?
Yes 0% No 0%
0 responsesStudent Reviews
No published reviews yet.
