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If the line (kx-2y=7) is parallel and distinct to the line (3x-6y=12), what will be the value of (k)?यदि रेखा (kx-2y=7) रेखा (3x-6y=12) के समांतर और अलग हो, तो (k) का मान क्या होगा?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (1)(1)
For parallel lines, (\frac{k}{3}=\frac{-2}{-6}), so (k=1). The constants ratio is different, so the lines are distinct parallel lines.समांतर होने के लिए (\frac{k}{3}=\frac{-2}{-6}), इसलिए (k=1)। नियतांकों का अनुपात अलग है, इसलिए रेखाएँ अलग समांतर हैं।
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