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Two routes are represented by \(4x+y=26\) and \(x+y=14\). At which point will the routes meet?रेखाएँ \(4x+y=26\) और \(x+y=14\) से दो मार्ग दर्शाए गए हैं। मार्ग किस बिंदु पर मिलेंगे?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: Point \(\left(4,10\right)\)बिंदु \(\left(4,10\right)\)
Subtracting the equations gives \(3x=12\), so \(x=4\) and \(y=10\). Whatever the context, the intersection point is the solution.दोनों समीकरण घटाने पर \(3x=12\), इसलिए \(x=4\) और \(y=10\)। संदर्भ कोई भी हो, प्रतिच्छेद बिंदु ही हल है।
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