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What is the \(y\)-intercept of the line \(7x+2y=28\)?रेखा \(7x+2y=28\) का \(y\)-अवरोध क्या है?
Answer and explanationउत्तर और व्याख्या
Correct answer:सही उत्तर: (0, 14)(0, 14)
To find the \(y\)-intercept, put \(x=0\). Then \(7(0)+2y=28\), so \(y=14\). Therefore, the line cuts the \(y\)-axis at \((0,14)\). Option B is the \(x\)-intercept because it is obtained by putting \(y=0\). Exam tip: For a \(y\)-intercept, always set \(x=0\).\(y\)-अवरोध ज्ञात करने के लिए \(x=0\) रखते हैं। तब \(7(0)+2y=28\), अर्थात् \(y=14\)। इसलिए रेखा \(y\)-अक्ष को \((0,14)\) पर काटती है। विकल्प B \(x\)-अवरोध है, क्योंकि उसमें \(y=0\) होता है। परीक्षा-युक्ति: \(y\)-अवरोध के लिए हमेशा \(x=0\) रखें।
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