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Where do the lines (x+4y=14) and (2x+4y=16) meet?

Answer and explanation

Correct answer: ( (2,3) )

The common point of two lines must satisfy both equations at the same time. The equations are \(x+4y=14\) and \(2x+4y=16\). Subtract the first equation from the second. The terms containing \(4y\) cancel, leaving \(x=2\). Substitute this value into the first equation: \(2+4y=14\), so \(4y=12\) and \(y=3\).

Therefore the lines meet at \((2,3)\), which is option A. Verification is easy: in the first equation, \(2+12=14\), and in the second, \(4+12=16\). Since the same point satisfies both equations, it is their intersection on the graph. Other listed points fail at least one equation.

Related tags

IntersectionSubtraction MethodGraph

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