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A newspaper seller sells (160) newspapers on the first day and (30) more newspapers each next day. On which day will (610) newspapers be sold?

Answer and explanation

Correct answer: 16

This is an AP with first term \(a=160\) and common difference \(d=30\). Sales on the \(n\)th day are \(a_n=160+(n-1)30\). Setting this equal to 610 gives \(160+(n-1)30=610\), so \((n-1)30=450\), \(n-1=15\), and \(n=16\). Therefore, 610 newspapers will be sold on the 16th day. On the 15th day, the sales would be 580, so that close option is incorrect. Exam tip: for a target value in an AP, equate it to \(a_n=a+(n-1)d\).

Related tags

Arithmetic ProgressionAp Word ProblemsNth TermLinear SequencesClass 10 MathematicsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions Ap

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