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The first row of a hall has 36 seats and each next row has 6 more seats. If the total number of seats is 1566, how many rows are there?

Answer and explanation

Correct answer: 18

The seat counts form an arithmetic progression with first term a = 36 and common difference d = 6. If there are n rows, the total is S_n = n/2[2a + (n − 1)d]. Substituting the data gives 1566 = n/2[72 + 6(n − 1)] = n/2(6n + 66) = 3n(n + 11). Therefore, n(n + 11) = 522. Testing the positive whole-number choices, n = 18 gives 18(18 + 11) = 18 × 29 = 522, so the number of rows is 18. Option D is correct. Direct verification gives the last row as 36 + 17×6 = 138; the average of the first and last rows is 87, and 87×18 = 1566. The other choices do not produce the stated total.

Related tags

MathematicsArithmetic ProgressionNumber Of TermsWord ProblemWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApClass 10 Mcq

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