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In a row arrangement the first row has 25 students and 22 rows have 1243 students in total. If the increase is equal then what is the increase?

Answer and explanation

Correct answer: 3

The row sizes form an arithmetic progression because each row increases by the same amount. The first term is a = 25, the number of rows is n = 22, and the total is S_22 = 1243. Apply S_n = n/2[2a + (n − 1)d]: 1243 = 22/2[2(25) + 21d] = 11(50 + 21d). Dividing by 11 gives 113 = 50 + 21d. Hence 21d = 63 and d = 3. Therefore, option B is correct. This value can be checked directly: the last row is 25 + 21(3) = 88, and the average row size is (25 + 88)/2 = 56.5; multiplying by 22 gives 1243. The other options fail the given total.

Related tags

MathematicsArithmetic ProgressionCommon DifferenceSum Of TermsWord Problems Based On ApsArithmetic Progressions (Ap)Arithmetic Progressions ApClass 10 Mcq

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